How To Check A Year Is Leap Year In Python

You can check if a year is a leap year in Python using the following logic:

def is_leap_year(year):
    if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
        return True
    else:
        return False

# Test the function
year = int(input("Enter a year: "))
if is_leap_year(year):
    print(f"{year} is a leap year.")
else:
    print(f"{year} is not a leap year.")
Code language: Python (python)

This code defines a function is_leap_year that takes a year as input and returns True if it’s a leap year and False if it’s not. The logic checks whether the year is divisible by 4 and not divisible by 100, or if it’s divisible by 400. If either of these conditions is met, the year is considered a leap year.

What is the formula for leap year in Python?

The formula to determine if a year is a leap year can be expressed in Python as follows:

def is_leap_year(year):
    return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)
Code language: Python (python)

This concise formula uses the same logic as mentioned earlier: a leap year is either divisible by 4 and not divisible by 100, or it is divisible by 400. The is_leap_year function will return True if the year is a leap year and False otherwise.

Is 1992 a leap year, use Python?

Yes, 1992 is a leap year in Python, as well as in the Gregorian calendar. You can use the is_leap_year function mentioned earlier to confirm this:

def is_leap_year(year):
    return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)

year = 1992
if is_leap_year(year):
    print(f"{year} is a leap year.")
else:
    print(f"{year} is not a leap year.")
Code language: Python (python)

When you run this code, it will print: “1992 is a leap year.” This is because 1992 satisfies the conditions for a leap year (divisible by 4 and not divisible by 100).

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